勤学早英语九上

1、D；2、B；3、C；4、A；5、C；6、C；7、D；8、A；9、C；10、B.二．填空题：（本大题共有6小题，每小题3分，共18分）11、3；12、103；13、310293.1；14、110；15、∠C=∠D或∠CAB=∠DBA或∠CAD=∠DBC或AD=BC；16、60.三．解答题：（本大题共52分）17．（本题满分5分）解：（π-3.14）0+22－(21)2+︱-2010︱=…………3′=2011…………2′18．（本题满分7分）解：…………2′…………2′…………1′…………1′…………1′19．（本题满分6分）∴△A1B1C1、△A2B2C2为所求作的三角形每图3分，结论没写扣1分20．（本题满分6分）解：（1）时间路程……………………………1′（2）答：9时走了4千米，10时走了9千米，12时走了15千米。………3′（3）答：他休息了30分钟。………………………………1′OxyABCA1B1C1A2B2C2看清题目认真作答第11页共11页（4）解：41.5610.5-129-15TSV千米/时答：他从休息后直至到达目的地这段时间的平均速度是4千米/时。………………………………1′21．（本题满分6分，每空1分）证明：∵AB∥CD(已知),∴∠B+∠BCD=180°(两直线平行，同旁内角互补)又∵∠B=∠D（已知）∴∠D+∠BCD=180°(等量代换)∴AD∥BC(同旁内角互补，两直线平行)∴∠E=∠DFE（两直线平行，内错角相等）22．（本题满分5分）解：P(甲获胜)=833212……2′P(乙获胜)=853220……2′所以，我认为乙获胜的概率较大……1′23．24．（本题满分10分）解：（1）∠γ=∠α+∠β……1′理由：过点P作PQ∥l1……1′∵PQ∥l1∴∠β=∠CPQ……1′∵PQ∥l1,l1∥l2∴PQ∥l2……1′∴∠α=∠DPQ……1′∴∠γ=∠α+∠β……1′(2)当点P在AB的延长线上运动时，∠γ=∠α-∠β……2′当点P在AB的延长线上运动时，∠γ=∠β-∠α……2′

Frank has just got off the train in the evening.He wants to call one of his friends to pick him up at once.He looks for a while and at last finds a telephone booth.But when he gets there, he sees a lady already in.There are no other public telephones nearby,so he has.to wait. He waits and waits.The lady on the phone is just talking andlaughing.She seems as if she doesn't notice Frank. After about half an hour,the lady puts down the receiver.Frank feels a bit released. She is finished finally,he thinks. But to his surprise,the lady picks it up again,fishes a coin from her pocket and pushes it into the slot."Oh, no!"Frank says to himself."She is making another call."