喝酒当喝汤
From:Scott HentTo:Mr.Kevin Lee SmithSubject:Price and a free-service-contractDate:June 18 ,2020,16:10:00Dear Mr.LeeAll products and services have prices.Price comparisons can be difficult to make because of consideration of credit terms,delivery,trade-in allowance,guarantees,quality and other forms of services.What price will produce the greatest profit over a long period of time?There is no way to really determine this price accurately.I s the price too high to produce a large volume?Too low to cover cost?No other area of marketing poerations has been more misundrerstood and subject to so much bad pratice.Many businesses pursre unsound pricing policees fro long periods witheout becoming aware of it.Prices are determined in various ways.For example,agricultural prices(cotton,wheat) are decided in large central-markets where forces of supply and demand exist.
堆高于岸
销售合同范本（中英文）合 同 CONTRACT 日期： 合同号码： Date: Contract No.: 买 方： (The Buyers) 卖方： (The Sellers) 兹经买卖双方同意按照以下条款由买方购进，卖方售出以下商品： This contract is made by and between the Buyers and the Sellers; whereby the Buyers agree to buy and the Sellers agree to sell the under-mentioned goods subject to the terms and conditions as stipulated hereinafter: (1) 商品名称: Name of Commodity： (2) 数 量： Quantity: (3) 单 价： Unit price: (4) 总 值： Total Value: (5) 包 装： Packing: (6) 生产国别： Country of Origin : (7) 支付条款： Terms of Payment: (8) 保 险： insurance: (9) 装运期限： Time of Shipment: (10) 起 运 港： Port of Lading: (11) 目 的 港： Port of Destination: (12)索赔：在货到目的口岸45天内如发现货物品质，规格和数量与合同不附，除属保险公司或船方责任外，买方有权凭中国商检出具的检验证书或有关文件向卖方索赔换货或赔款。 Claims: Within 45 days after the arrival of the goods at the destination, should the quality, Specifications or quantity be found not in conformity with the stipulations of the contract except those claims for which the insurance company or the owners of the vessel are liable, the Buyers shall, have the right on the strength of the inspection certificate issued by the C.C.I.C and the relative documents to claim for compensation to the Sellers (13)不可抗力：由于人力不可抗力的原由发生在制造，装载或运输的过程中导致卖方延期交货或不能交货者，卖方可免除责任,在不可抗力发生后，卖方须立即电告买方及在14天内以 空邮方式向买方提供事故发生的证明文件，在上述情况下，卖方仍须负责采取措施尽快发货。 Force Majeure : The sellers shall not be held responsible for the delay in shipment or non-deli-very of the goods due to Force Majeure, which might occur during the process of manufacturing or in the course of loading or transit. The sellers shall advise the Buyers immediately of the occurrence mentioned above the within fourteen days there after . the Sellers shall send by airmail to the Buyers for their acceptance a certificate of the accident. Under such circumstances the Sellers, however, are still under the obligation to take all necessary measures to hasten the delivery of the goods. (14）仲裁：凡有关执行合同所发生的一切争议应通过友好协商解决，如协商不能解决，则将分歧提交中国国际贸易促进委员会按有关仲裁程序进行仲裁，仲裁将是终局的，双方均受其约束，仲裁费用由败诉方承担。 Arbitration : All disputes in connection with the execution of this Contract shall be settled friendly through negotiation. in case no settlement can be reached, the case then may be submitted for arbitration to the Arbitration Commission of the China Council for the Promotion of International Trade in accordance with the Provisional Rules of Procedure promulgated by the said Arbitration Commission . The Arbitration committee shall be final and binding upon both parties and the Arbitration fee shall be borne by the losing parties. 买方： 卖方: 这是一份中英文合同，去掉中文，就是你想要的范本。
苦瓜老太婆
参考答案一、1．D 2．D 3．C 4．B 5．C 6．D 7．B 8．A 9．C 10．D二、11．甲 12． 13．3 14．≥4(如果写，给3分) 15． 16．2.5≤≤7.5(只写出≤7.5或≥2.5，给2分；缺等号，扣1分)方案一：由图像信息可设；∵图像经过(30，2700) ∴把(30，2700)代入得30k+1200=2700 得k=50∴y1=50x+1200；方案二：由图像信息可设y2 =kx+1800；∵图像经过(30，2700) ∴把(30，2700)代入y2 =kx+1800得30k+1800=2700 得k=30∴y2=30x+1800；由题意得改进后的方案二为：y2 =(30+m)x+1800当x=40时，y1 =50×40+1200=3200y2 =(30+m)×40+1800=40m+3000∵两种方案的报酬差额不超过100元∴y1-y2 ≤100且y2 –y1≤100即3200-(40m+3000)≤100且(40m+3000)-3200≤100得∴m≥2.5且m≤7.5即2.5≤≤7.5三、17．解：原式= 6分(每个对给2分)= 8分18．解：(1) 2分∴ 4分 2)∵∴ 6分∴ 8分其它解法酌情给分19． 评分说明： (1)作出垂线，给3分，若用三角板画直角，没有弧线痕迹，只给2分； (2)作出点B处的弧线，标上点B，给1分 (3)作出点D处的弧线，标上点D，给1分 (4)连接AB，BC，AD，DC，给2分 (5)写出结论，给1分 结论：四边形ABCD就是所求的正方形(其它画法酌情给分) 20．(1)证明： 1分 2分∵∴ 3分∴方程总有两个不相等的实数根。 4分(2)∴∴ 6分 得∴∴ 8分21．(1)证明：∵正方形ABCD ∴ 1分 ∵，DE∥AC ∴DE=OA，DE∥OA ∴四边形AOED是平行四边形 3分 ∴OF=FD 又OB=OD ∴BF=3DF 5分 (2)解：延长EO交AB于G 6分 ∵AB=BC=2，∠ABC= ∴AC= 7分 ∴OA=AC= ∵AD∥OE，AD⊥AB ∴OE⊥AB ∴AG=AB=1 8分 ∴OG= 又OE=AD=2 ∴EG=OG+OE=3 9分 ∴AE= 10分 其它解法酌情给分22．解：(1)①40 2 5 3分②4 5 5分（2）发言次数增加3次的学生人数为：40×(1-20%-30%-40%)=4(人) 8分全班增加的发言总次数为：40%×40×1+30%×40×2+4×3=16+24+12=52(次) 答：第二天发言次数增加3次的学生有4人，全班增加的发言总次数为52次. 12分23．解：(1)①(，)； 2分②由题意： 3分 解得 4分∴点P(，) 5分(2)1. 8分(3)设B(a，b)，则A(，).∵点A在函数y＝的图象上，∴ 9分∴. 10分∴B在直线上．∴此直线与轴的夹角为过Q作垂线段，就是所求的QB最短时的线段，垂足为B，则可求得B(3，) 12分24．(1)9 3分 (2)①， 5分②由已知得，菱形ABCD的边长为2，当点在线段BC上时， ∵ ∴ 解得 6分当点在BC延长线上时， ∵ ∴ 解得 综上所述，当或时，. 7分 (3)①如图甲，当点在线段BC上时，易证△为等边三角形 由，可求得 8分 由点B(，)，C(1，0)可求得直线BC解析式： 同理可求得直线CD解析式： ∵∥轴， ∴点E(， 9分 ∴= ∵ ∴ ∴ 10分 如图乙，当点在线段BC延长线上时，由得，，∴ 综上所述，或. 12分 ② 14分 说明：在R△中， ∴ ∴.……就这些？给个采纳呗
