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时光飞逝,做好初二数学期末复习准备,考场上充分发挥自己的数学能力。沉着才见英雄本色。下面由我为你整理的初二数学上期末试卷,希望对大家有帮助!

一、选择题

1.某地一天的最高气温是12℃,最低气温是﹣2℃,则该地这天的温差是()

A.﹣10℃ ℃ ℃ D.﹣14℃

2.据报道,目前我国“天河二号”超级计算机的运算速度位居全球第一,其运算速度达到了每秒338 600 000亿次,数字338 600 000用科学记数法可简洁表示为()

×108 ×109 ×107 ×109

3.如图,放置的一个机器零件(图1),若从正面看到的图形如(图2)所示,则从上面看到的图形是()

A. B. C. D.

4.下列说法正确的是()

A.有理数分为正数和负数

B.有理数的相反数一定比0小

C.绝对值相等的两个数不一定相等

D.有理数的绝对值一定比0大

5.单项式﹣23a2b3的系数和次数分别是()

A.﹣2,8 B.﹣8,5 ,8 D.﹣2,5

6.若a+b<0且ab<0,那么()

<0,b>0 <0,b<0

>0,b<0 ,b异号,且负数绝对值较大

7.把弯曲的道路改直,就能缩短路程,其中蕴含的数学原理是()

A.过一点有无数条直线 B.两点确定一条直线

C.两点之间线段最短 D.线段是直线的一部分

8.某品牌商品,按标价八折出售,仍可获得10%的利润.若该商品标价为275元,则商品的进价为()

元 元 元 元

9.如图,两块直角三角板的直顶角O重合在一起,若∠BOC= ∠AOD,则∠BOC的度数为()

° ° ° °

10.适合|2a+5|+|2a﹣3|=8的整数a的值有()

个 个 个 个

二、填空题

11.﹣ 的相反数是.

12.过某个多边形的一个顶点的所有对角线,将这个多边形分成6个三角形,这个多边形是边形.

13.如图,数轴上点A、B、C所对应的数分别为a、b、c,化简|a|+|c﹣b|﹣|a+b﹣c|=.

14.如图,P1是一块半径为1的半圆形纸板,在P1的左下端剪去一个半径为 的半圆后得到图形P2,然后依次剪去一个更小的半圆(其直径为前一个被剪掉半圆的半径)得图形P3,P4,…,Pn,…,记纸板Pn的面积为Sn,试通过计算S1,S2,猜想得到Sn﹣1﹣Sn=(n≥2).

三、解答题

15.计算题

(1)30×( ﹣ ﹣ );

(2)﹣14﹣(1﹣)× ×[1﹣(﹣2)3].

16.解方程:

(1) ﹣ =1

(2) ﹣ =.

17.如图,已知线段a,b,用尺规作一条线段AB,使AB=2a﹣b(不写作法,保留作图痕迹).

18.先化简,再求值(﹣x2+3xy﹣ y2)﹣(﹣ x2+4xy﹣ y2),其中x=2,y=1.

19.新年快到了,贫困山区的孩子想给资助他们的王老师写封信,折叠长方形信纸装入标准信封时发现:若将信纸如图①连续两次对折后,沿着信封口边线装入时,宽绰有;若将信纸如图②三等分折叠后,同样方法装入时,宽绰 cm,试求信纸的纸长和信封的口宽.

20.雾霾天气严重影响市民的生活质量,在今年元旦期间,某校七年级一班的同学对“雾霾天气的主要成因”就市民的看法做了随机调查,并对调查结果进行了整理,绘制了不完整的统计图表(如下图),观察分析并回答下列问题.

组别 雾霾天气的主要成因 百分比

A 工业污染 45%

B 汽车尾气排放 m

C 炉烟气排放 15%

D 其它(滥砍滥伐等) n

(1)本次被调查的市民共有人;

(2)补全条形统计图;

(3)图2中区域B所对应的扇形圆心角为度.

21.如图,已知∠COB=2∠AOC,OD平分∠AOB,且∠COD=25°,求∠AOB的度数.

22.甲仓库有水泥100吨,乙仓库有水泥80吨,要全部运到A、B两工地,已知A工地需要70吨,B工地需要110吨,甲仓库运到A、B两工地的运费分别是140元/吨、150元/吨,乙仓库运到A、B两工地的运费分别是200元/吨、80元/吨,本次运动水泥总运费需要25900元.(运费:元/吨,表示运送每吨水泥所需的人民币)

(1)设甲仓库运到A工地水泥为x吨,请在下面表格中用x表示出其它未知量.

甲仓库 乙仓库

A工地 x

B工地 x+10

(2)用含x的代数式表示运送甲仓库100吨水泥的运费为元.(写出化简后的结果)

(3)求甲仓库运到A工地水泥的吨数.

23.已知线段AB=12,CD=6,线段CD在直线AB上运动(A在B的左侧,C在D的左侧).

(1)当D点与B点重合时,AC=;

(2)点P是线段AB延长线上任意一点,在(1)的条件下,求PA+PB﹣2PC的值;

(3)M、N分别是AC、BD的中点,当BC=4时,求MN的长.

一、选择题

1.某地一天的最高气温是12℃,最低气温是﹣2℃,则该地这天的温差是()

A.﹣10℃ ℃ ℃ D.﹣14℃

【考点】有理数的减法.

【分析】根据题意用最高气温12℃减去最低气温﹣2℃,根据减去一个数等于加上这个数的相反数即可得到答案.

【解答】解:12﹣(﹣2)=14(℃).故选:C.

2.据报道,目前我国“天河二号”超级计算机的运算速度位居全球第一,其运算速度达到了每秒338 600 000亿次,数字338 600 000用科学记数法可简洁表示为()

×108 ×109 ×107 ×109

【考点】科学记数法—表示较大的数.

【分析】科学记数法的表示形式为a×10n的形式,其中1≤|a|<10,n为整数.确定n的值时,要看把原数变成a时,小数点移动了多少位,n的绝对值与小数点移动的位数相同.当原数绝对值>1时,n是正数;当原数的绝对值<1时,n是负数.

【解答】解:数字338 600 000用科学记数法可简洁表示为×108.

故选:A.

3.如图,放置的一个机器零件(图1),若从正面看到的图形如(图2)所示,则从上面看到的图形是()

A. B. C. D.

【考点】简单组合体的三视图.

【分析】根据从上边看得到的图形是俯视图,可得答案.

【解答】解:从上边看是等宽的三个矩形,

故选:D.

4.下列说法正确的是()

A.有理数分为正数和负数

B.有理数的相反数一定比0小

C.绝对值相等的两个数不一定相等

D.有理数的绝对值一定比0大

【考点】有理数;相反数;绝对值.

【分析】根据有理数的分类、绝对值的性质,可得答案.

【解答】解:A、有理数分为正数、零、负数,故A不符合题意;

B、负数的相反数大于零,故B不符合题意;

C、互为相反数的绝对值相等,故C符合题意;

D、绝对值是非负数,故D不符合题意;

故选:C.

5.单项式﹣23a2b3的系数和次数分别是()

A.﹣2,8 B.﹣8,5 ,8 D.﹣2,5

【考点】单项式.

【分析】根据单项式系数、次数的定义来求解.单项式中数字因数叫做单项式的系数,所有字母的指数和叫做这个单项式的次数.

【解答】解:单项式﹣23a2b3的系数和次数分别是﹣8,5,

故选B.

6.若a+b<0且ab<0,那么()

<0,b>0 <0,b<0

>0,b<0 ,b异号,且负数绝对值较大

【考点】有理数的乘法;有理数的加法.

【分析】根据a+b<0且ab<0,可以判断a、b的符号和绝对值的大小,从而可以解答本题.

【解答】解:∵a+b<0且ab<0,

∴a>0,b<0且|a|<|b|或a<0,b>0且|a|>|b|,

即a,b异号,且负数绝对值较大,

故选D.

7.把弯曲的道路改直,就能缩短路程,其中蕴含的数学原理是()

A.过一点有无数条直线 B.两点确定一条直线

C.两点之间线段最短 D.线段是直线的一部分

【考点】线段的性质:两点之间线段最短.

【分析】根据线段的性质,可得答案.

【解答】解:把弯曲的道路改直,就能缩短路程,其中蕴含的数学原理是两点之间线段最短,

故选:C.

8.某品牌商品,按标价八折出售,仍可获得10%的利润.若该商品标价为275元,则商品的进价为()

元 元 元 元

【考点】一元一次方程的应用.

【分析】设商品的进价为x元,由已知按标价八折出售,仍可获得10%的利润,可以表示出出售的价格为(1+10%)x元,商品标价为275元,则出售价为275×80%元,其相等关系是售价相等.由此列出方程求解.

【解答】解:设商品的进价为x元,根据题意得:

(1+10%)x=275×80%,

x=200.

故商品的进价为200元.

故选:B.

9.如图,两块直角三角板的直顶角O重合在一起,若∠BOC= ∠AOD,则∠BOC的度数为()

° ° ° °

【考点】角的计算.

【分析】此题“两块直角三角板”可知∠DOC=∠BOA=90°,根据同角的余角相等可以证明∠DOB=∠AOC,由题意设∠BOC=x°,则∠AOD=5x°,结合图形列方程即可求解.

【解答】解:由两块直角三角板的直顶角O重合在一起可知:∠DOC=∠BOA=90°

∴∠DOB+∠BOC=90°,∠AOC+∠BOC=90°,

∴∠DOB=∠AOC,

设∠BOC=x°,则∠AOD=5x°,

∴∠DOB+∠AOC=∠AOD﹣∠BOC=4x°,

∴∠DOB=2x°,

∴∠DOB+∠BOC=3x°=90°

解得:x=30

故选A.

10.适合|2a+5|+|2a﹣3|=8的整数a的值有()

个 个 个 个

【考点】绝对值.

【分析】此方程可理解为2a到﹣5和3的距离的和,由此可得出2a的值,继而可得出答案.

【解答】解:如图,由此可得2a为﹣4,﹣2,0,2的时候a取得整数,共四个值.

故选:A.

二、填空题

11.﹣ 的相反数是 .

【考点】相反数.

【分析】求一个数的相反数就是在这个数前面添上“﹣”号.

【解答】解:﹣ 的相反数是﹣(﹣ )= .

故答案为: .

12.过某个多边形的一个顶点的所有对角线,将这个多边形分成6个三角形,这个多边形是八边形.

【考点】多边形的对角线.

【分析】根据n边形对角线公式,可得答案.

【解答】解:设多边形是n边形,由对角线公式,得

n﹣2=6.

解得n=8,

故答案为:八.

13.如图,数轴上点A、B、C所对应的数分别为a、b、c,化简|a|+|c﹣b|﹣|a+b﹣c|=0.

【考点】整式的加减;数轴;绝对值.

【分析】根据数轴上点的位置判断出绝对值里边式子的正负,利用绝对值的代数意义化简,去括号合并即可得到结果.

【解答】解:根据题意得:a<0

∴a<0,c﹣b>0,a+b﹣c<0,

∴|a|+|c﹣b|﹣|a+b﹣c|=﹣a+(c﹣b)+(a+b﹣c)=﹣a+c﹣b+a+b﹣c=0.

故答案为0.

14.如图,P1是一块半径为1的半圆形纸板,在P1的左下端剪去一个半径为 的半圆后得到图形P2,然后依次剪去一个更小的半圆(其直径为前一个被剪掉半圆的半径)得图形P3,P4,…,Pn,…,记纸板Pn的面积为Sn,试通过计算S1,S2,猜想得到Sn﹣1﹣Sn=( )2n﹣1π.(n≥2).

【考点】扇形面积的计算.

【分析】由P1是一块半径为1的半圆形纸板,在P1的左下端剪去一个半径为 的半圆后得到图形P2,得到S1= π×12= π,S2= π﹣ π×( )2.同理可得Sn﹣1= π﹣ π×( )2﹣ π×[( )2]2﹣…﹣ π×[( )n﹣2]2,Sn= π﹣ π×( )2﹣ π×[( )2]2﹣…﹣ π×[( )n﹣2]2﹣ π×[( )n﹣1]2,它们的差即可得到.

【解答】解:根据题意得,n≥2.

S1= π×12= π,

S2= π﹣ π×( )2,

Sn﹣1= π﹣ π×( )2﹣ π×[( )2]2﹣…﹣ π×[( )n﹣2]2,

Sn= π﹣ π×( )2﹣ π×[( )2]2﹣…﹣ π×[( )n﹣2]2﹣ π×[( )n﹣1]2,

∴Sn﹣1﹣Sn= π×( )2n﹣2=( )2n﹣1π.

故答案为( )2n﹣1π.

三、解答题

15.计算题

(1)30×( ﹣ ﹣ );

(2)﹣14﹣(1﹣)× ×[1﹣(﹣2)3].

【考点】有理数的混合运算.

【分析】(1)原式利用乘法分配律计算即可得到结果;

(2)原式先计算乘方运算,再计算乘法运算,最后算加减运算即可得到结果.

【解答】解:(1)原式=15﹣20﹣24=15﹣44=﹣29;

(2)原式=﹣1﹣ × ×9=﹣ .

16.解方程:

(1) ﹣ =1

(2) ﹣ =.

【考点】解一元一次方程.

【分析】解一元一次方程的一般步骤:去分母、去括号、移项、合并同类项、系数化为1,据此求出每个方程的解是多少即可.

【解答】解:(1)去分母,得2(5+2x)﹣3(10﹣3x)=6

去括号,得10+4x﹣30+9x=6

移项,得4x+9x=6﹣10+30

合并同类项,得13x=26

系数化为1,得x=2

(2)去分母,得﹣(﹣x)=×

去括号,得﹣

移项,得

合并同类项,得

系数化为1,得x=

17.如图,已知线段a,b,用尺规作一条线段AB,使AB=2a﹣b(不写作法,保留作图痕迹).

【考点】作图—复杂作图.

【分析】首先作射线,再截取AD=DC=a,进而截取BC=b,即可得出AB=2a﹣b.

【解答】解:如图所示:线段AB即为所求.

18.先化简,再求值(﹣x2+3xy﹣ y2)﹣(﹣ x2+4xy﹣ y2),其中x=2,y=1.

【考点】整式的加减—化简求值.

【分析】首先化简(﹣x2+3xy﹣ y2)﹣(﹣ x2+4xy﹣ y2),然后把x=2,y=1代入化简后的算式,求出算式的值是多少即可.

【解答】解:(﹣x2+3xy﹣ y2)﹣(﹣ x2+4xy﹣ y2)

=﹣x2+3xy﹣ y2+ x2﹣4xy+ y2

=﹣﹣xy+y2

当x=2,y=1时,

原式=﹣×22﹣2×1+12

=﹣2﹣2+1

=﹣3

19.新年快到了,贫困山区的孩子想给资助他们的王老师写封信,折叠长方形信纸装入标准信封时发现:若将信纸如图①连续两次对折后,沿着信封口边线装入时,宽绰有;若将信纸如图②三等分折叠后,同样方法装入时,宽绰 cm,试求信纸的纸长和信封的口宽.

【考点】一元一次方程的应用.

【分析】设信纸的纸长为12xcm,则信封的口宽为(4x+)cm,根据信纸的折法结合信封的口宽不变即可得出关于x的一元一次方程,解之即可得出结论.

【解答】解:设信纸的纸长为12xcm,则信封的口宽为(4x+)cm.

根据题意得:3x+,

解得:x=,

∴12x=,4x+.

答:信纸的纸长为,信封的口宽为11cm.

20.雾霾天气严重影响市民的生活质量,在今年元旦期间,某校七年级一班的同学对“雾霾天气的主要成因”就市民的看法做了随机调查,并对调查结果进行了整理,绘制了不完整的统计图表(如下图),观察分析并回答下列问题.

组别 雾霾天气的主要成因 百分比

A 工业污染 45%

B 汽车尾气排放 m

C 炉烟气排放 15%

D 其它(滥砍滥伐等) n

(1)本次被调查的市民共有200人;

(2)补全条形统计图;

(3)图2中区域B所对应的扇形圆心角为108度.

【考点】条形统计图;统计表;扇形统计图.

【分析】(1)根据条形图和扇形图信息,得到A组人数和所占百分比,求出调查的市民的人数;

(2)根据A、C组的百分比求得其人数,由各组人数之和可得D组人数,即可补全条形统计图;

(3)持有B组主要成因的市民百分比乘以360°求出答案.

【解答】解:(1)从条形图和扇形图可知,A组人数为90人,占45%,

∴本次被调查的市民共有:90÷45%=200人,

故答案为:200;

(2)∵A组的人数为200×45%=90(人),C组的人数为200×15%=30(人),

∴D组人数为200﹣90﹣60﹣30=20,

补全条形统计图如下:

(3)∵B组所占百分比为60÷200=30%,

∴30%×360°=108°,

即区域B所对应的扇形圆心角的度数为:108°,

故答案为:108.

21.如图,已知∠COB=2∠AOC,OD平分∠AOB,且∠COD=25°,求∠AOB的度数.

【考点】角的计算;角平分线的定义.

【分析】先设∠AOC=x,则∠COB=2∠AOC=2x,再根据角平分线定义得出∠AOD=∠BOD=,进而根据∠COD=25°列出方程,解方程求出x的值,即可得出答案.

【解答】解:设∠AOC=x,则∠COB=2∠AOC=2x.

∵OD平分∠AOB,

∴∠AOD=∠BOD=.

∴∠COD=∠AOD﹣∠AOC=﹣x=.

∵∠COD=25°,

∴°,

∴x=50°,

∴∠AOB=3×50°=150°.

22.甲仓库有水泥100吨,乙仓库有水泥80吨,要全部运到A、B两工地,已知A工地需要70吨,B工地需要110吨,甲仓库运到A、B两工地的运费分别是140元/吨、150元/吨,乙仓库运到A、B两工地的运费分别是200元/吨、80元/吨,本次运动水泥总运费需要25900元.(运费:元/吨,表示运送每吨水泥所需的人民币)

(1)设甲仓库运到A工地水泥为x吨,请在下面表格中用x表示出其它未知量.

甲仓库 乙仓库

A工地 x 70﹣x

B工地 100﹣x x+10

(2)用含x的代数式表示运送甲仓库100吨水泥的运费为﹣10x+15000元.(写出化简后的结果)

(3)求甲仓库运到A工地水泥的吨数.

【考点】一元一次方程的应用.

【分析】(1)根据题意填写表格即可;

(2)根据表格中的数据,以及已知的运费表示出总运费即可;

(3)根据本次运送水泥总运费需要25900元列方程化简即可.

【解答】解:(1)设甲仓库运到A工地水泥的吨数为x吨,则运到B地水泥的吨数为吨,

乙仓库运到A工地水泥的吨数为(70﹣x)吨,则运到B地水泥的吨数为(x+10)吨,

补全表格如下:

甲仓库 乙仓库

A工地 x 70﹣x

B工地 100﹣x x+10

故答案为:70﹣x;100﹣x;

(2)运送甲仓库100吨水泥的运费为140x+150=﹣10x+15000;

故答案为:﹣10x+15000;

(3)140x+150+200(70﹣x)+80(x+10)=25900,

整理得:﹣130x+3900=0.

解得x=30

答:甲仓库运到A工地水泥的吨数是30吨.

23.已知线段AB=12,CD=6,线段CD在直线AB上运动(A在B的左侧,C在D的左侧).

(1)当D点与B点重合时,AC=6;

(2)点P是线段AB延长线上任意一点,在(1)的条件下,求PA+PB﹣2PC的值;

(3)M、N分别是AC、BD的中点,当BC=4时,求MN的长.

【考点】线段的和差.

【分析】(1)根据题意即可得到结论;

(2)由(1)得AC= AB,CD= AB,根据线段的和差即可得到结论;

(3)需要分类讨论:①如图1,当点C在点B的右侧时,根据“M、N分别为线段AC、BD的中点”,先计算出AM、DN的长度,然后计算MN=AD﹣AM﹣DN;②如图2,当点C位于点B的左侧时,利用线段间的和差关系求得MN的长度.

【解答】解:(1)当D点与B点重合时,AC=AB﹣CD=6;

故答案为:6;

(2)由(1)得AC= AB,

∴CD= AB,

∵点P是线段AB延长线上任意一点,

∴PA+PB=AB+PB+PB,PC=CD+PB= AB+PB,

∴PA+PB﹣2PC=AB+PB+PB﹣2( AB+PB)=0;

(3)如图1,∵M、N分别为线段AC、BD的中点,

∴AM= AC= (AB+BC)=8,

DN= BD= (CD+BC)=5,

∴MN=AD﹣AM﹣DN=9;

如图2,∵M、N分别为线段AC、BD的中点,

∴AM= AC= (AB﹣BC)=4,

DN= BD= (CD﹣BC)=1,

∴MN=AD﹣AM﹣DN=12+6﹣4﹣4﹣1=9.

初二期末考试卷

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A. if(是否) tea and coffee were harmful to people B. if the twin brothers should be sentenced to death C. if tea and coffee did harm to people's health and caused them to die D. whether tea and coffee were useful or not 48. The King decided to let the brothers live ______. A. if they wanted to obey his rules B. if they agreed to drink tea and coffee every day one of them drink several cups of tea each day while the other had several cups of coffee D. if they agreed to have several cups of tea every day 49. The brother who had drunk tea every day lived ______. A. until he was over 83 B. until he was 83 C. until the other had been dead for several years D. until he had drunk tea for a few years 50. Today the Swedish drink ______. A. much more coffee than teaB. much tea and coffee C. little tea and coffeeD. much tea but little coffee C Soon it would be the holidays. But before that,there were the end of year exams. All the students had been working hard for some time. If they didn't pass,they would have to retake the exams in September. There were usually a few who failed,but Kate decided not to be one of them. She had worked hard all day,but just before the exams she was working so hard that her sister was worried about her. She was staying up too late. The night before the first exam, Barbala insisted(坚持) that she should have an early night and take a sleeping pill. She promised(许诺) to wake her in the morning. As she was falling asleep,Kate was worried in case(万一) she over-slept. Her mind kept jumping from subject to subject. At last,with the help of the pill,she fell asleep. In no time at all,she was sitting in the examination hall, looking at the paper. She couldn't answer any of the questions. Everyone round her was writing pages and pages. However hard she thought,she couldn't find anything to write about. She kept looking at her watch. Time was running out. There was only one hour left. 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The students are going to help the farmers to pick apples next Sunday.(就画线部分提问) ____ ____ the students ____ ____ ____ next Sunday? 七.根据中文和英文提示词语,写出正确的句子。所给英文词语全部用上。注意大、小写和标点符号。(共5小题,每小题2分) 66. 躺着看书对你的眼睛有害。read,in bed,bad,your eyes __________________________________________________ 67. 我出生于1980年6月18号。I,born,June 18,1980 __________________________________________________ 68. 你不要在这条河里游泳。you,swim,in the river __________________________________________________ 69. 今天是几号?what,the,today __________________________________________________ 70. 凯特昨天在回家的路上买了一些蔬菜。Kate,buy,some,vegetables,way,home,yesterday __________________________________________________ 八.书面表达。请根据图示的内容,把故事情节补充完整,要求语句通顺、全文意思连贯。(共10分) 注意: 1. 第1格要求至少写出两个完整的句子; 2. 第2、3、4、5格要求将句子补充完整,单词数不限; 3. 第6格要求将You'd better…补充完整后,再至少写出一个完整的句子。 It was Christmas Day. My friends came to my house. We danced and sang together. We enjoyed ourselves very much. How time flied! It was time for us to exchange(交换) our Christmas presents. I went to my bedroom go get the presents. When I went into the room,to my surprise,I found my friend Ben 71 my diary. It was impolite to do that! But Ben was laughing! I was 72 that I was about to cry. Ben felt a bit sorry when he found me standing 73 him. I hated him and shouted at him. He went out of my room at once and went home without saying goodbye to any of us. One of my best friends Any asked me why Ben 74 so early. I told her what had just happened. She seemed to know what should do. She said to me,“Don't shout at him. You'd better 75.” 参考答案 一. 看图拼写单词 1. envelope 2. skating3. college4. stamps 5. flower 6. coin7. window 8. emperor 9. fast 10. kite 二. 单项填空 11. D12. D13. D14. B15. B16. C17. A18. B19. C20. C 21. B22. A23. C24. B25. B26. B27. A28. A29. B30. B 三. 完形填空 31. D32. A33. C34. B35. D36. B37. A38. D39. D40. D 四. 阅读理解 五. 单词拼写 56. understand57. February58. fashio59. jeans60. sad 六. 句型转换 61. What,did,buy 62. Does,teach 63. How,long,did,work 64. didn't,go 65. What,are,going,to,do 七. 看词组句 66. Reading in bed is bad for your . I was born on June 18,1980. 68. You'd better not swim in the river69. What's the date today? 70. Kate bought some vegetables on her way home yesterday. 八. 书面表达 71. was reading72. so angry73. in front of74. went back / home / away 75. pardon him / get on well with him / say sorry to him.

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